Chapter 1: Worksheet 1 Jack K. Cohen Colorado School of Mines
Symbol Problems, Inequalities
Suggested Problems
Section 1.1: 1, 5, 11, 15, 17, 19
- (1.56) Express the area A of a square as a function of its perimeter P. Sketch a graph of this function—label your axes.
- (1.58) Express the volume V of a sphere as a function of its surface area S. Sketch a graph of this function—label your axes.
- If a > 0, correctly remove the absolute value signs from | a|. Same for | - a|.
- If a < 0, correctly remove the absolute value signs from | a|. Same for | - a|.
- True confession time. Problems like 1.19 drive me crazy! One day, the Voice said, ``Use the symbols, Luke''. Huh? Symbols? Oh yeah, symbols ...algebra ...do a general case! Our inequality looks like
B≤| Dx + E|≤C. By dividing by a positive constant, we can simplify to
b≤| x - a|≤c (convince yourself!). The ``interesting'' case is
0≤b≤c, so assume this.
By doing the cases x≤a and x > a separately,
show that the solution to the simplified inequality,
b≤| x - a|≤c, (
0≤b≤c) is the union of the closed intervals,
[a - c, a - b] and
[a + b, a + c].
- Why are these cases not ``interesting''?
-
b≤| x - a|≤c with b > c.
-
b≤| x - a|≤c with b < 0.
- Write down the solution of the closely related inequalities:
-
b≤| x - a| < c
-
b < | x - a|≤c
-
b < | x - a| < c
- (1.19) Use the general inequality solution of the previous problems to check up on
2≤| 4 - 5x|≤4. Don't forget to put the problem into the right form by ``dividing by a positive constant''.
- (1.17) What happens to the general inequality solution if
c→ + ∞? Check up on
| 1 - 3x| > 2. (Hint: explain why this is equivalent to
2 < | 1 - 3x| < + ∞.)
- (1.15) What happens to the general inequality solution if b = 0? Check up on
| 3 - 2x| < 5. Is the solution of
0 < | 3 - 2x| < 5 the same as for the given inequality?